Syntax error using pointer

Question

int main() {
    char const* path = "/bla/bla";
    struct zip *teste;
    int *errorp;
    &teste   = *zip_open(path, ZIP_CREATE, errorp);
    return 0;
}

It returns this error:

main.cpp: In function ‘int main()’:
main.cpp:11:50: error: lvalue required as left operand of assignment
     &teste   = *zip_open(path, ZIP_CREATE, errorp);

I guess it’s because I’m not assigning anything to errorp but does it need to save exactly? when I assign a number to it from the conversion error.

I am following that documentation.

Answer 1

I have two things to tell you: first you are programming in C and not C++, and this is worrying, you are making a basic mistake, so it would not be the case to learn the mechanisms of language before learning to do something more complex?

That’s how it works:

int main() {
    char const* path = "/bla/bla";
    int *errorp;
    struct zip *teste = zip_open(path, ZIP_CREATE, errorp);
}

I put in the Github for future reference.

The function call syntax is completely wrong, I can’t imagine why you put the & and *, in it.

There is at least another problem visible in this code that will soften the execution (does not allocate memory to errorp), and something tells me that’s not even how you use this library, so solving this problem will do little good. The problem described is solved.