List in Python

Question

How do I receive 10 integers and receive them separated by spaces in the same row in the list and print them in reverse order.

I remember it was something like this:

variavelA, variavelB = input().split(' ')

Answer 1

With the following entry: 1 2 3 4 5 6 7 8 9 0

The following output is obtained:

0
9
8
7
6
5
4
3
2
1

With the following code:

[print(x) for x in input().split()[::-1]]

And a reverse list ['0', '9', '8', '7', '6', '5', '4', '3', '2', '1'] with input().split()[::-1]

Answer 2

Starting from the premise that the user will type the numbers separated by spaces, that is, since it has to be on the same line, it is not possible to check each typing (you could do the checking after typing)but, abstracting this check you could do everything a single command line:

print(' '.join((input('entre com os numros: ').split(' '))[::-1]))

If the user logs in 10 20 30 40 50 60 70 80 90 100, you would have the exit:

100 90 80 70 60 50 40 30 20 10

Separately explaining:
Explaining each part of the control from the center to the ends.

input('entre com os numros: '):
Receives the user’s typing into an object in memory, string type;

.split(' '):
Create a list from the typed string, where each element is the substring immediately preceding the space.

[::-1])
Make a Slice by inverting the list.

' '.join()
Converts the list to a string back.

print()
Displays the result

Implementing separately:
The same commands executed on the single line above, now implemented separately:

# Inputando os números
numbers = input('entre com os numeros: ')

# Convertendo para uma lista:
lst_numbers = numbers.split(' ')

# Invertendo a lista
lst_inverted = lst_numbers[::-1] 

# Convertendo a lista invertida para uma string
str_inverted = ' '.join(lst_inverted)

# Apresentando o resultado
print(str_inverted)

Exit:

'100 90 80 70 60 50 40 30 20 10'