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I’m wanting to use Foreign key but I’m not getting it. This instruction SQL will create a table called tbl_estado with 4 columns id, nome, uf, pais and in the column pais will enter the key Foreign that will be searched in tbl_pais the id of the country which is the column id.
$where = axitech20 (bank)
$tablep = tbl_pais
$tableet = tbl_estado

$sql8   = "CREATE TABLE IF NOT EXISTS $aonde.$tablee (
            id INT(6) UNSIGNED ZEROFILL NOT NULL AUTO_INCREMENT PRIMARY KEY,
            nome        VARCHAR(75) DEFAULT NULL,
            uf          VARCHAR(5) DEFAULT NULL,
            pais        INT(6) DEFAULT NULL KEY '??????????' ($tablep)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=28";
I’m not getting to do the relationship that’s something in there ?????????? of the instruction. Can help me to hit the foreign key?
Have you tried to check on mysql documentation ?
– gmsantos
I tried yes that’s how I managed to create the instruction but I’m not getting the instructions that go there
???????– Marcos Vinicius
FOREIGN KEY (product_category, product_id) REFERENCES product(category, id)– gmsantos