json_encode - Invalid JSON

Question

I created a PHP code to fetch information from a database (Mysql) and "transform" into JSON. I used the json_encode for such.

The output JSON seemed to be correct, but when I use some JSON validator, it always returns an error Unexpected token.

What most intrigues me is that if I manually type the output JSON into the validator, it works! If I give a Ctrl+C and Ctrl+V, the error occurs.

To check the JSON result: http://devsa.url.ph/? Cod=all

What can it be?

<?php
include('connectdb.php');

$something = $_GET['cod'];
$sqlcode = mysql_query("Select descricao from Produtos Where codigo='$something'");
$sqlcode2 = mysql_query("Select descricao from Produtos");

$jsonObj = array();

if ($something == 'all') {
    while ($result = mysql_fetch_object($sqlcode2)) {
        $jsonObj[] = $result;
    }
} else {
    while ($result = mysql_fetch_object($sqlcode)) {
        $jsonObj[] = $result;
    }
}

$final_res = json_encode($jsonObj);

echo $final_res;
?>

Answer 1

A likely diagnosis may be the type of coding.

To fix this, enter the file type header, leave no character type before and after output, make sure your tag <?php is the first thing in the file and remove the tag ?> end of file, or add a exit;:

header('Content-Type: application/json');
$final_res = json_encode($jsonObj);
echo $final_res;
exit;

Check which the encoding from your database, from the PHP file that is printing the data and from the file that is receiving the data. If possible, put them all in UTF-8 without GOOD ^english.

Complement:

Note that there are two files with GOOD at the beginning.

the code for php header:

header("Content-Type: application/json; charset=utf-8;");