-2
Put in J3
:
=SE(F3='A';'A';'')
Replicate to other cells.
-2
0
Hey, try it like this:
In the cell: J3
Enter the formula: =SE(CONT.SE(F:F;"A")-LIN()+3>0;"A";"")
Then drag down and sideways at will!
It did not work, he left all cells blank, soon after I removed "+3>0" and he played the letter "A" in all cells, when I should just play the amount of "A" right for the left table
It gets a little bad, leave all the rows in the "F" column selected, because if you have any content on top or down in the cells, tbm will count
I did +3 because I imagined your data to be on line 3. Which line they are on. Give an example of the result you want, print.. thus it becomes easier to elaborate a solution.
They were, but they’re not. I moved the table to another location
In column 1 there must be three letters "A" one at the bottom of the other without presenting empty lines (blank cells) and so on
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– danieltakeshi
Lucas Augusto Coelho Lopes, would you be able to put one letter under the other? because in this case the letters were separated according to the left table
– Elienay Junior
I don’t get it, like this, @Elienayjunior?
– Lucas Augusto Coelho Lopes
In column number 1 would be the letter "A" in each row without displaying blank cells
– Elienay Junior
Letter "A" under "A"
– Elienay Junior
the same way you replicated the formula to the right, you can replicate it down, if that’s what I got.
– Lucas Augusto Coelho Lopes
I’m saying, without presenting the blank columns of F3=A, F4=A and F5=A, got it??
– Elienay Junior
one below the other without giving spaces
– Elienay Junior
Then I don’t know
– Lucas Augusto Coelho Lopes