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I’m making a game in pygame and need to know the last position of the matrix for the movement of enemies.
It has to be according to the size of the matrix, that is, the last column and the first column of the matrix has to collide with the edges of the map.
This is my code:
import pygame
from pygame.locals import *
from sys import exit
from random import randint
#define os parametros do canhao
def Canhao(C, x, y):
R = []
for i in range(len(C)):
a = C[i][0] + x
b = C[i][1] + y
R.append((a, b))
return(tuple(R))
#variaveis
T = []
C = ((0,15), (4,5), (12,5), (15,0), (18,5), (26,5), (30,15))
XC = 460
YC = 400
CorFundo = (0, 0, 0)
lar = 30
esp = 5
alt = 30
xp = 330
yp = 380
movx, movy = 5,5
direcao = 1
y = 0
#criando a matriz
j = 0
while j < 5:
i = 0
while i < 12:
o = (10+i*(lar+esp), 10+j*(alt+esp), (0, 180-j*20, 255-j*20), (0, 0, 127))
T.append(o)
i = i + 1
j = j + 1
TiroAtivo = False
#iniciando
pygame.init()
pygame.font.init()
tela = pygame.display.set_mode((700, 500))
clock = pygame.time.Clock()
pygame.display.set_caption('Space invaders')
#loop infinito
fim = False
while not fim:
pygame.display.flip()
tela.fill((0,0,0))
#movimentacao## usar o len(T) para testar se a movimentacao chegou no fim da tela
if direcao == 1:
movx += 5
if movx == 280:
direcao = 2
movx -= 5
movy += 5
if direcao == 2:
movx -= 5
if movx < 0:
direcao = 1
movy += 5
movx += 5
#desenha o canhao
pygame.draw.polygon(tela, (50,130,50), Canhao(C, XC, YC), 0)
#desenha os inimigos
for i in range(len(T)):
pygame.draw.rect(tela, T[i][2], (movx+T[i][0], movy+T[i][1], lar, alt), 0)
pygame.draw.rect(tela, T[i][3], (movx+T[i][0], movy+T[i][1], lar, alt), 2)
#colisao
for i in range(len(T)):
if movx+T[i][0] <= xp <= movx+T[i][0]+lar and movy+T[i][1] <= yp <= movy+T[i][1]+alt:
del(T[i])
xp = 0
## yp = 0
TiroAtivo = False
break
if yp < 5:
TiroAtivo = False
#desenha o tiro
if TiroAtivo:
pygame.draw.circle(tela, (127, 90, 90), (xp, int(yp)), 3, 0)
pygame.draw.circle(tela, (127, 90, 90), (xp, int(yp)+3), 3, 0)
pygame.draw.circle(tela, (127, 90, 90), (xp, int(yp)+6), 3, 0)
pygame.draw.circle(tela, (127, 90, 90), (xp, int(yp)+9), 3, 0)
yp = yp - 10
#movimentacao do canhao
Teclas = pygame.key.get_pressed()
if Teclas[K_LEFT]:
XC = XC - 10
if Teclas[K_RIGHT]:
XC = XC + 10
if Teclas[K_SPACE] and TiroAtivo == False:
xp = XC + C[3][0]
yp = 380;
TiroAtivo = True
#tela de game over
if len(T) == 0:
# definindo o texto
fonte_Arial = pygame.font.SysFont("Arial", 60)
texto = fonte_Arial.render("Game over!",1,(255,255,255))
# copiando o texto para a superfície
tela.blit(texto, [200, 150])
time_passed = clock.tick(30)
for event in pygame.event.get():
if event.type == QUIT:
fim = True
pygame.display.quit()
I’m using a variable for drive which is the movx and movy, only that I want to move according to the first and last column of the matrix.
For example, if the last column is destroyed, the penultimate one becomes the last and the movement continues until the end of the screen.