Where to use accumulators in a unique peer-review algorithm?

Asked

Viewed 285 times

1

Where should I fit the accumulators of this code I have written for now?

 #include <stdio.h>

         int main()
         {

         int N;
         int somapar;
         int somaimpar;

         do{
         printf("\n Digite um número qualquer: ");
         scanf("%d", &N);

         if (N % 2 == 0){
         printf("\n Número escolhido é par!");
         }

         else {
         printf("\n Número escolhido é ímpar");
         }
         }while (N >= 0);

         printf("\n");

         return 0;
         }

The enunciation of the algorithm is this:

Write an algorithm to show on the screen whether each N number typed by the user is even or odd. The algorithm should also show on the screen the sum of all even numbers, the sum of all odd numbers, the percentage of even numbers and the percentage of odd numbers entered. The algorithm must terminate its execution if the user enters a number less than zero.

c algorithm while accountant

  • If you have another question, ask a new question, do not change what has already been answered.

2 answers

2


Each of them must be placed inside the if after all it is in it that it is decided whether it is even or odd. Do not forget to reset the variable at startup to not catch dirt from memory.

#include <stdio.h>

int main() {
    int N;
    int somapar = 0;
    int somaimpar = 0;
    do {
        printf("\n Digite um número qualquer: ");
        scanf("%d", &N);
        if (N % 2 == 0) {
            printf("\n Número escolhido é par!");
            somapar += N;
        } else {
            printf("\n Número escolhido é ímpar");
            somaimpar += N;
        }
    } while (N >= 0);
    printf("\nTotal de ímpares é %d e total de pares é %d\n", somaimpar, somapar);
}

Behold working in the ideone. And in the repl it.. Also put on the Github for future reference.

The percentage and other things are up to you.

  • friend I’m still struggling.

0

I SET AN EXAMPLE TO HELP YOU WITH THE MEDIA AND SUM, THE PERCENTAGE IS UP TO YOU.

#include <stdio.h>

int main() {
    // INICIALIZANDO VARIAVEIS COM 0.
    int N;
    int par = 0;
    int impar = 0;
    int somapar=0;
    int mediapar=0;
    int somaimpar=0;
    int mediaimpar = 0;

    do {
        printf("\n Digite um número qualquer: ");
        scanf("%d", &N);

        // SE O NUMERO FOR PAR ELE ENTRA AQUI
        if (N % 2 == 0) {
            printf("Número escolhido é par!\n");
            par = par + 1;
            somapar = somapar + N;
            mediapar = somapar / par;
        } 

        // SE NÃO ENTRA AQUI
        else{
            printf("\Número escolhido é ímpar!\n");
            impar = impar + 1;
            somaimpar = somaimpar + N;
            mediaimpar = somaimpar / impar;
        }
    } while (N > 0);

    // EXIBINDO RESULTADO NA TELA
    printf("------------------RESULTADO-------------------");
    printf("\nO Total de ímpares é %d e o total de pares é %d.", impar, par);
    printf("\nA soma dos numeros pares é: %d.", somapar);
    printf("\nA média dos numeros pares é: %d.", mediapar);
    printf("\nA soma dos numeros impares é: %d.", somaimpar);
    printf("\nA média dos numeros impares é: %d.", mediaimpar);
}

Browser other questions tagged c algorithm while accountant

You are not signed in. Login or sign up in order to post.