Write member access to a pointer structure instead of using the "->" operator

Question

How would you write this assignment:

p1->caracter='B';

otherwise using * instead of ->?

Answer 1

You first take the value of the object and then access the member normally:

(*p1).caracter = 'B';

I put in the Github for future reference.

This operator is just a form of overreact the pointer and access its member.