1
Good afternoon guys, you hit the following doubt:
When I define within an integer variable the zero the left it returns me in echo a number nothing to see, I wonder why:
Follows exemplification:
<?php
echo $inteiro = 015;
//me retorna o seguinte valor: 13 gostaria de saber o pq?
?>
6
Because the 015 is the octagonal representation of the 13th decimal.
copied from the manual
<?php
$a = 1234; // decimal number
$a = -123; // a negative number
$a = 0123; // octal number (equivalent to 83 decimal)
$a = 0x1A; // hexadecimal number (equivalent to 26 decimal)
$a = 0b11111111; // binary number (equivalent to 255 decimal)
?>
perfect answer
Thank you for the reply Manuel
Funny that even forcing the guy: $int = (int) 015; PHP still identifies the result as octagonal and changes the value of the variable.
@Kazzkiq independent of notation it remains an integer. Notation is just a different way of writing a number or a character. Barely comparing is like writing in Portuguese or English, the number remains the same.
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A left zero signals to php that this number should be interpreted in base 8(octal). Integer with 0 to the left is printed as another number
– rray
Supplementary reading: http://answall.com/questions/25031/
– Bacco