Subtract dates in PHP

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1

I’m with a project where I need to change information from week to week.

Is there an automated PHP function that can help me subtract today’s date by a base date that I set. For example:

$datadehoje = (int)date("d/m/Y");
$database = (int)date("15/07/2018");
$resultado = $datadehoje - $database;

The code above is misspelled but is to illustrate more or less what I wanted. The project will have information for months and would not want to have to create an algorithm for this.

php date

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2 answers

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No way to convert a date into int and get something meaningful. You have to make a difference using the date type itself to get a significant result, which will be a date range. Then you can get the amount of days that is a text, if you want you can convert that text to number if you are going to do accounts with it.

$database = date_create('2018-07-15');
$datadehoje = date_create();
$resultado = date_diff($database, $datadehoje);
echo date_interval_format($resultado, '%a');

I put in the Github for future referenceto.

1

One of the ways to do an operation with dates on PHP is:

// a partir da data de hoje
echo date("d/m/Y",strtotime(date("Y-m-d")."+12 month"));

// a partir de outras datas
echo date("d/m/Y",strtotime(date("Y-m-d",strtotime($data_de_referencia))."-12 month"));

Reference date()

Reference strtotime()

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