Download event problem in "href"

Question

I have a problem where I need to find a file on the server Linux with the name of the value of <a href> and download it when you click on the link.

the file path is /var/www/html/ligacoes (there are several folders and inside the folders are the files, example /var/www/html/ligacoes/interno/2014/01/30/1391088944.2621-11_35_44-4002-1006.WAV

Answer 1

Solution Listing Files by ID of a Table

I imagine you have a chart or a way to make one from/to file ID for its respective path (path).

Let’s assume you have the table with the fields ID and CAMINHO, thus:

ID   NOME
1    /arquivos/planilha.xls
2    /arquivos/documento.pdf

And on the page you have manage to list the files like this:

<a href="download.php?id=1">planilha.xls</a>
<a href="download.php?id=2">documento</a>

So in the script download.php you need to make a logic like this:

$id_arquivo = $_GET['id'];
$caminho = recuperaCaminhoPorId($id_arquivo); //implementar esta função em algum lugar
readfile($caminho); //lê o arquivo e manda para o usuário

Obviously it is good for you to do some treatments, such as when the script does not receive any parameter or does not find the ID in the database.

See the job documentation readfile().

If you want to force the download of files that by default would be opened in the browser (HTML, text, image, etc.), you can also put headers, such as:

header('Content-Type: application/octet-stream');
header('Content-Disposition: attachment; filename=' . basename($caminho));

Note that headers need to be set before writing the file, i.e., before calling the function readfile();.

Solution with direct link to the file

After seeing the question update, it was clear that the downloadable files are in a folder available on the HTTP server.

To make the file available, you can create a link with the path relative to the server root.

<a href="/interno/2014/01/30/1391088944.2621-11_35_44-4002-1006.WAV">Download</a>

If you want to list the files of a folder using PHP and create the links automatically, you can use the function scandir() PHP to list the files and make a for to print the links.

Example:

$files = scandir($dir);
$basedir = '/var/www/html'; 
foreach($files as $f) {
    if($f != '.' && $f != '..') {
        echo '<a href="' . str_replace($basedir,'',$f) . '">'
            . basename($f) . '</a>';
    }
}

This is just a simple idea that you can adapt to your need.

Answer 2

I don’t know if I got the question right, but to search for a file on a linux server, you can use Ack/grep. Install the package, if it’s Ubuntu:

$ sudo apt-get install ack-grep

And to search the file you can use:

$ ack nome_do_arquivo.txt ~/

The second parameter being "~/" the directory from where you want to search.

And to create a download link for that file, you need to put it in a folder that has web access permissions. A simple example would be the Apache www folder.

Answer 3

For a file to be accessed through a link, you need to send the correct path to it, follow example.

You informed that the site is at /var/www/html/ligacoes, you probably access the browser by the url http://localhost/ligacoes, following your example above, the file /var/www/html/ligacoes/interno/2014/01/30/1391088944.2621-11_35_44-4002-1006.WAV can be accessed in two ways:

<!-- Link Relativo -->
<a href="/interno/2014/01/30/1391088944.2621-11_35_44-4002-1006.WAV">Baixar</a>
<!-- Link Absoluto -->
<a href="http://localhost/ligacoes/interno/2014/01/30/1391088944.2621-11_35_44-4002-1006.WAV">Baixar</a>

I hope I answered your question!