Error class expected!

Question

Error class expected!

Asked 10 years, 2 months ago

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1

With this code I get the error:

error: class expected

import javax.swing.JOptionPane;  

public class MenorIdade {  
    public static void main(String[] args) {  
        String[] nomes = new String[5];  
        int [] idades = new int[5];  
        int maisJovem = 0;  

        for (int i = 0; i <= 4; i++) {  
            nomes[i] = JOptionPane.showInputDialog("Informe o nome");  
            idades[i] = int.parseInt(JOptionByte.showInputDialog("Informe a idade"));

            if (idades[i] < idades[maisJovem]) {  
                maisJovem = i;  
            }
        }  

        JOptionPane.showMessageDialog(null, nomes[maisJovem] + " é mais jovem e tem " + idades[maisJovem] + " anos.");  

    }  
}

2 answers

1

Code modifications:

public static void main(String[] args) 
{
    String[] nomes = new String[5];  
    int [] idades = new int[5];  
    int maisJovem = 0;  
    String showInputDialog = "";
    for (int i = 0; i <= 4; i++) {  
        nomes[i] = JOptionPane.showInputDialog("Informe o nome");  
        showInputDialog = JOptionPane.showInputDialog("Informe a idade");
        idades[i] = Integer.parseInt(showInputDialog);
        if (idades[i] < idades[maisJovem]) {  
            maisJovem = i;  
        }
    }  
    JOptionPane.showMessageDialog(null, nomes[maisJovem] + " é mais jovem e tem " + idades[maisJovem] + " anos.");          
}

It would be a valid way, @Maria. At first I didn’t understand why the String showInputDialog; intermediate, but I ended up seeing. But, even functional, is not necessary, since it can do the parse directly.

– Gustavo Cinque

2014/08/29 at 13:36
I’ll edit my answer so Camuratti can look at the two forms, okay?

– Gustavo Cinque

2014/08/29 at 13:37
@Gustavocinque, quiet do yes...!

– Maria

2014/08/29 at 13:44
@Gustavocinque in relation to parse, in my opinion this code needs to be improved, because there is no criticism in the contents that can be typed...

– Maria

2014/08/29 at 13:49
Um, it’s just that I’ve always used the parse on input, hehe. Speed on writing and reading, for me.

– Gustavo Cinque

2014/08/29 at 13:53
So at this point I disagree and if the guy type letter instead of number? not even a block try catch he put understand

– Maria

2014/08/29 at 13:54
1

You’re right. If it did, it would make a beautiful NumberFormat.

– Gustavo Cinque

2014/08/29 at 14:03
1

Thanks for the help, @Maria!!

– Camuratti

2014/08/29 at 16:37

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by Gustavo Cinque • **594** points · Answer 1 · 2014-08-29T11:14:21+00:00

On line 11:

idades[i] = int.parseInt(JOptionByte.showInputDialog("Informe a idade"));

You cannot use the primitive type of a class to make method calls, so the correct one would be Integer.parseInt();. I don’t know if it would be just me, but my IDE(Eclipse) didn’t recognize the class JOptionByte.

One way would be to replace the part JOptionByte and use the JOptionPane even, getting like this:

idades[i] = Integer.parseInt(JOptionPane.showInputDialog("Informe a idade"));