1
How do I compare elements from 2 lists, and return the amount of elements in common ? For example:
a=[1, 2, 3, 4, 5]
b=[6, 7, 8, 9, 10, 1, 2, 11, 22]
This should return 2, because there are only 2 elements in common.
1
How do I compare elements from 2 lists, and return the amount of elements in common ? For example:
a=[1, 2, 3, 4, 5]
b=[6, 7, 8, 9, 10, 1, 2, 11, 22]
This should return 2, because there are only 2 elements in common.
2
Just make the intersection of the two lists and then see the number of elements.
comum=len(set(a).intersection(b))
2
Set a variable on a repeated worthwhile 0 who will serve as an accountant:
>>> num_repetido = 0
Loop the list to see if any of the numbers repeat and then add in the repeated num_variable:
for num in a:
if num in b:
num_repetido += 1
And finally print on the screen the final value of the variable on a repeated:
>>> print(num_repetido)
It is worth noting that there are several ways to do this, as the friend above put it, everything depends on what you need. Hug.
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Can lists contain duplicate elements? That is, without two numbers 1 in
a
andb
, must be accounted for once or twice?– Woss