1
I receive in JSON a date field "created_at": "2013-01-08T20:11:48Z" and wanted to present on the screen in the formed of Brazil but I can’t use Simpledateformat to format and present in any way.
1
I receive in JSON a date field "created_at": "2013-01-08T20:11:48Z" and wanted to present on the screen in the formed of Brazil but I can’t use Simpledateformat to format and present in any way.
2
Follows solution below:
String dataJson = "2013-01-08T20:11:48Z".replaceAll("T", " ").replaceAll("Z", "");
SimpleDateFormat format = new SimpleDateFormat("yyyy-mm-dd HH:mm:ss");
Date dataFormatada = new Date(format.parse(dataJson).getTime());
System.out.println(dataFormatada);
Access here to see the result.
1
Try using the new Java 8 date API this way:
public static void main(String[] args) {
String data = "2013-01-08T20:11:48Z";
DateTimeFormatter originalFormat = DateTimeFormatter.ofPattern("yyyy-MM-dd'T'HH:mm:ss'Z'");
DateTimeFormatter targetFormat = DateTimeFormatter.ofPattern("dd/MM/yyyy HH:mm:ss");
// Com isso já da pra fazer várias manipulações interessantes
LocalDateTime dateTime = LocalDateTime.parse(data, originalFormat);
// ou assim
DateTimeFormatter formatador = DateTimeFormatter
.ofLocalizedDateTime(FormatStyle.MEDIUM)
.withLocale(new Locale("pt", "br"));
System.out.println(data);
System.out.println(dateTime.format(targetFormat));
System.out.println(dateTime.format(formatador));
}
See working on Ideone.
Other references:
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The date is now leaving like this: Thu Mar 09 08:14:00 GMT-03:00 ..........
– Hugo
On my computer appeared like this: Tue Jan 08 20:11:48 GMT 2013
– karanalpe
Check your computer’s UTC configuration
– karanalpe