Is it possible to make a selection list in the form of a loop?

Question

It is possible to make a selection list (UIPickerView) in loop form? Put the month of January right after December, I say.

Answer 1

Just like the @Rivas said, there is no very practical way to do it. I’ll try to illustrate a little better the explanation above:

You need to multiply the amount of elements by a high number, 100, for example, but be careful, because depending on the object used, multiplying by a very high number can cause slowness.

- (NSInteger)pickerView:(UIPickerView *)pickerView numberOfRowsInComponent:(NSInteger)component {
    return self.mesesArray.count * 100;
}

Then to get the title correctly it is necessary to use the operator mod (%) to obtain the 12-month line.

- (NSString *)pickerView:(UIPickerView *)pickerView titleForRow:(NSInteger)row forComponent:(NSInteger)component
{
    return self.mesesArray[row % self.mesesArray.count];
}

And to finish position the selection of UIPicker through the middle of the list, or some next line. Do this in some view startup method, such as the viewDidLoad.

- (void)viewDidLoad
{
    [super viewDidLoad];
    self.mesesArray = @[@"Janeiro",@"Fevereiro",@"Março",@"Abril",@"Maio",@"Junho",@"Julho",@"Agosto",@"Setembro",@"Outubro",@"Novembro",@"Dezembro"];

    [self.pickerView selectRow:self.mesesArray.count * 50
                   inComponent:0
                      animated:NO];

}

The final result this:

Answer 2

Yes, but the method is kind of gambiarra, there is an automatic code for it so much that apple itself does. I’ll explain; Smplismente make a list of 100 copies of the same sequence, then make this Picker move to sequence #50( item #50*12 months).