How to do sequence in R?

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3

I need to do this sequence in a repeating structure to use with a larger N, but I’m not getting it done, does anyone have any idea how to do this?

n=8
names <- c (seq(1 , n), seq(2,n+1 ), seq (3,n+2), seq(4 ,n+3), seq(5,n+5 ),seq(6,n+5),seq(7, n+6 ), seq (8,n+7))

Thanks in advance..

r
  • 3

    I think your code is wrong, wouldn’t it seq(5,n+4)? It makes more sense by the logic of the other sequences.

2 answers

3


If what you want is a way to make the sequence more dynamic, you can use the following:

n=8
names <- rep(1:n, n)+rep(0:(n-1), each=n)
#[1]  1  2  3  4  5  6  7  8  2  3  4  5  6  7  8  9  3  4  5  6  7  8
#[23]  9 10  4  5  6  7  8  9 10 11  5  6  7  8  9 10 11 12  6  7  8  9
#[45] 10 11 12 13  7  8  9 10 11 12 13 14  8  9 10 11 12 13 14 15

That way you create the sequence 1:n n times, and adds 0, 1, 2...n-1 each 1:n.

  • That’s what I was looking for, thank you very much :)

1

Complementing with one more response option, you can also use lapply.

criar_seq <- function(x){
    seq(x, (n+x-1))
}

n <- 8
lapply(1:n, criar_seq)

This will return a list of n sequences with the progression of one more. If you want to put the data as vector, just apply unlist.

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