Insert data into a vector to then print and multiply

Question

Write an algorithm that reads two vectors of 10 positions and make the multiplication of the elements of the same index, placing the result in a third vector. Show the resulting vector.

I wanted to first show the typed values and then start to elaborate the step by step multiplication. That’s how I would start?

int main(void) {

    int vetorA[10] = {0};
    int vetorB[10] = {0};

    int a,b;

    for(a = 0; a < 10; a++){
        printf("Vetor A: \n");
        a=getchar();


    for(b = 0; b < 10; b++){
        printf("Vetor B: \n");
        b=getchar();





        }
    }

    return 0;
}

Answer 1

Vc is initiating its vectors with only one value {0} instead of having 10 values: {0,11,22,31,48,54,62,71,84,99}.

You better put the length of the array instead of 10: for(b = 0; b < vetorA.length; b++).

To "show" vc must concatenate "Vector B: n" with vectorB[b], see that the "b" between brackets is to indicate the position of the vector, i.e.: printf("Vetor B: \n" + vetor[b]);

To do the multiplication vc does a for to traverse the positions of the two vectors using the "Count" to indicate the position of the vectors.

for(i = 0; i < 10; i++)
{
    printf("Valor multiplicado: \n" + (vetorA[i] * vetorB[i]);
}

Answer 2

There are several errors in this code, it’s not even close to doing something useful. So at least it starts right:

#include <stdio.h>

int main(void) {
    int vetorA[10] = { 0 };
    int vetorB[10] = { 0 };
    for (int i = 0; i < 10; i++) {
        printf("Vetor A: \n");
        scanf("%d", &vetorA[i]);
    }
    for (int i = 0; i < 10; i++){
        printf("Vetor B: \n");
        scanf("%d", &vetorB[i]);
    }
}

Behold working in the ideone. And in the repl it.. Also put on the Github for future reference.

This is the right start, now to print is the same algorithm, only changes the scanf() for printf(). Multiplication is done in the same way as it does without being a vector, but the variable always has the index [], will make another loop, or together with the loop printing.

Answer 3

to print only the values on the screen for now.. would be so?

int main(void) {

    int vetorA[10] = { 0 };
    int vetorB[10] = { 0 };

    int i;

    for(i = 0; i < 10; i++){
        printf("Vetor A: \n");
        scanf("%d", &vetorA[i]);

    for(i = 0; i < 10; i++){
        printf("Vetor B: \n");
        scanf("%d", &vetorB[i]);

        }   

    }

    for(i = 0; i < 10; i++){

    printf("Vetor A: %d\n ",vetorA[i]);

    printf("Vetor B: %d\n ", vetorB[i]);

    }

    system("pause");
    return 0;
}