1
Situation:
I need to create a multi-dimensional array script. Example:
Table 1 >> Campos id and name
Table 2 >> Campos id and telephone
Current script:
#!/bin/bash
declare -A arr
arr[tabela1]=id
arr[tabela2]=id
for i in "${!arr[@]}"
do
echo "Tabela: $i"
echo "Campo: ${arr[$i]}"
done
return
Problem:
How to make a multidimensional array and a loop to insert, in addition to the script id, several columns; example: 'name', 'telephone' etc, as shown in Situation?
Thank you!
1
From what I understand, you want an array that stores information id and name. If it is...
Creating bash array is simpler than you think. Example:
#!/bin/bash
array_( "nome1" "nome2" "nome3" )
#technique 1 for print all elements
echo "${array_[@]:0}"
#technique 2 for print all elements
for ((id=0; id<{#$array_[@]}; id++)); do
echo "Bands: ${array_[$id]}"
done
ps: In bash, the use of ${#array[@]} is the same as saying: - "Hey array, how many elements are stored in you?"
Using the above example to print the name, can be done something like this:
#!/bin/bash
bands=("slayer" "sodom" "megadeth")
for ((i=0; i<${#bands[@]}; i++)); do
echo "Bands: ${bands[$i]}"
done
output:
Bands: slayer
Bands: sodom
Bands: megadeth
In theory we know that we will have to work with two arrays and print them in parallel, so I did this (pseudo-)code:
** Even though it is not so recommended to use the eval, but beauty... that’s just one example! ;)
Using the code below demonstrates a 'technique' to print only the id.
#!/bin/bash
#uncomment to enable debug
#set -x
main() {
local idx_tab1=$(set -- {1..5} && echo ${@})
local idy_tab2=$(set -- {1..5} && echo ${@})
display=('x1=${idx_tab1[@]}' 'y1=${idy_tab2[@]}')
for id in "${display[@]}"; do
eval ${id[@]}
done
echo "idx_tab1: ${x1[@]//\ /$'\n'idx_tab1: }"
echo "" # skip one line --//--
echo "idy_tab2: ${y1[@]//\ /$'\n'tdy_tab2: }"
}
main ${@:1}
output:
idx_tab1: 1
idx_tab1: 2
idx_tab1: 3
idx_tab1: 4
idx_tab1: 5
idy_tab2: 1
tdy_tab2: 2
tdy_tab2: 3
tdy_tab2: 4
tdy_tab2: 5
Putting all Together
Example 1: manual, no loop.
source
#!/bin/bash
#uncomment to enable debug
#set -x
main() {
#array "name" for get "id"
local table1=("t1_nome1" "t1_nome2" "t1_nome3")
local table2=("t2_nome1" "t2_nome2" "t2_nome3")
echo "Table: 1"
echo "Column: ${table1[@]:0}"
echo $'\n'
echo "Table: 2"
echo "Column: ${table2[@]:0}"
}
main ${@:1}
output
Table: 1
Column: t1_nome1 t1_nome2 t1_nome3
Table: 2
Column: t2_nome1 t2_nome2 t2_nome3
Example 2, with loop while:
#!/bin/bash
#uncomment to enable debug
#set -x
main() {
#array "name" for get "id"
local table1=("t1_nome1" "t1_nome2" "t1_nome3")
local table2=("t2_nome1" "t2_nome2" "t2_nome3")
local len_t=("table1" "table2")
local id=1
while [[ "$id" -lt "${#len_t[@]}" ]];
do
echo "Table: [$id]"
echo "Column: ${table1[@]:0}"
let "id = $id + 1"
echo $'\n'
echo "Table: [$id]"
echo "Column: ${table2[@]:0}"
done
}
main ${@:1}
output:
Table: [1]
Column: t1_nome1 t1_nome2 t1_nome3
Table: [2]
Column: t2_nome1 t2_nome2 t2_nome3
Anyway, to catch the id of the tables, I have to add them to the array so that I can take the exact size and make a loop from 1 (not from scratch! ) up to the maximum array size. This is what I did using while: [[ "$id" -lt "${#array[@]}" ]].
Well... I think that’s what you need! :)
Browser other questions tagged array loop script bash multidimensional-array
You are not signed in. Login or sign up in order to post.
Bash does not support (directly) multidementional arrays. You can work around the problem (1) by using (strings, texts, etc) multilevel separators (EX: CVS), (even within bash Arrays values), (2) using XML, JSON or (3) by migrating to perl, python, ruby, etc.
– JJoao
Thank you @Jjoao!
– Evert
If you need help with examples of any of the "proposals", says!
– JJoao
@JJOAO thanks!! I was needing to assemble a script and meet this demand for the link below, but in the end everything worked out. Thank you very much!! http://answall.com/questions/86491/manter-configura%C3%A7%C3%B5es-ao-alterar-url-wordpress-tema-Adventure-Organic-them/86665#86665
– Evert