command given ajax json for php

Question

JS file:

var jsonsave = [];

var dado = new Object();
dado.nome= "João";
dado.cpf = "000";
dado.teste = "teste";
var jason = JSON.stringify(dado);
jsonsave.push(jason);


$.ajax({
               type: "POST",
               dataType: "JSON",
               url: "http://localhost/moodle/my/index.php",
               data: "data="+jsonsave+"&ENVIO_RESPOSTAS=true",
               success: function(data){
                   console.log('foi');
               },
               error: function(data)
               {
                    console.log(data);

               }
           });

Php file:

$arquivo = $_POST['data'];
$value= json_decode($arquivo, TRUE);

I call the php page by ajax, but I can’t get the json values, come null, anyone have any idea?

Answer 1

Try to send the data in pure JSON format:

 ...
 dataType:"json",
 url: "http://localhost/moodle/my/index.php",
 data: jason, 
 ...

And in PHP, to get the values:

$json = json_encode($_POST);
var_dump($json);

Observing:

In order for you to be able to check if PHP has received the data, you must show the return on the terminal, or in some other way. Because I did a test and found that even the way you are doing, PHP received the data. So I recommend the following change to be able to check this:

 success: function(data){
     console.log(data);
 },

Response obtained by executing this change in the code you provided:

//string(62) ""{\"nome\":\"Jo\u00e3o\",\"cpf\":\"000\",\"teste\":\"teste  //\"}""

Having the data in this format, in PHP, doesn’t make much sense, maybe what you want is to get a array/object. In this case, you are using the inverse function. The correct one would be json_decode:

$json = json_decode($_POST['data']);
var_dump($json);

And the exit:

//object(stdClass)#1 (3) {
//  ["nome"]=>
//  string(5) "João"
//  ["cpf"]=>
//  string(3) "000"
//  ["teste"]=>
//  string(5) "teste"
//}

Answer 2

I use it a lot:

var PrimeiroNome=$("#InputPrimeiroNome").val();

$.post("pagina2.php",{nome:PrimeiroNome}).done(function(resultado){
   $("div #recebeValor").html(resultado);
});

Basically inside the javascript will open a page 2.php in the background where will send the input value with the id ="Inputprimeironome" attribute to a PHP POST with the name "name" and will return the echo of this php page and assign the div #receivedValue With some jokes so can make the site well dynamic

Answer 3

In my case it worked the one used by Bruno Almeida:

var Primeironome=$("#Inputprimeironome"). val();

$.post("pagina2.php",{name:Primeironome}). done(Function(result){ $("div #receive"). html(result); });

and in php I used: $arr = json_decode($_POST['name']); echo $arr

Answer 4

Try to use as follows:

    $.ajax({
                   type: "POST",
                   url: "http://localhost/moodle/my/index.php",
                   data: function (data){
                      data.data = jason;
                      data.envio_resposta= true;
                   },
                   success: function(data){
                       console.log('foi');
                   },
                   error: function(data)
                   {
                        console.log('n foi');

                   }
               });

Hug,

Answer 5

I use it this way:

$postdata = file_get_contents('php://input');
$json = json_decode($postdata);