Calculation of the multiple of 10 greater than or equal to a value

Question

use module 10; Example:

7  4  8  9  3  1  0  7  2 <== Dados
x  x  x  x  x  x  x  x  x
2  1  2  1  2  1  2  1  2 <== Peso
=  =  =  =  =  =  =  =  =
14 4  16 9  6  1  0  7  4 <= Resultado
1+4=5 1+6=7
//resultado da multiplicação, cujo valor for maior que 10 (dez), os dígitos do resultado devem ser
//somados, resultando um valor menor que 10 (dez);

5 4 7 9 6 1 0 7 4 = 43 <== Resultado Final
//Somatório do resultado das multiplicações = 43

So far so good. Now comes my problem. How to find Multiple of 10 greater or equal to the sum of 43?

My current code:

for (int i = 0; i <= soma; i += 10) {
    if ((i % 10) == 0) {
       if (i >= soma) {
          Multiplo = i;
       }
    }
}

Answer 1

To find the nearest 10 multiples, you can make use of the following pseudo-code:

int multiplo;
if(quociente % 10 != 0)
{
  int quociente = soma / 10;
  multiplo = (quociente+1)*10;
} else
{
  multiplo = soma;
}

The first variable will take only the entire portion of the division quotient by 10, and then the nearest multiplier is the successor of the quotient multiplied by 10.

I avoided declaring them in the same line to avoid any problem with simultaneous declaration of variables, since one depends on the other, if the dependency does not exist, error occurs.

Answer 2

I know it’s old, but there’s a simpler way....

if(soma%10==0){
    multiplo = soma;
}else{
    multiplo = (soma-(soma%10))+10 
}