7
I wonder if it is possible to start this structure type pointer with an address, without needing to point to another variable, or allocate memory.
typedef struct{
char nome[20];
int idade;
}pessoa;
pessoa leonardo;
pessoa *p;
p = &leonardo;
p->idade = 23;
printf("%d", p->idade);
Or allocating memory.
pessoa *p = malloc(sizeof(pessoa));
6
Can:
p = (pessoa*)1234;
Now, you gotta know what you’re gonna do with it...
Here gave error..
Here did not give......
Says invalid type of argument *, has int
show the code
You have to declare "p" as pointer, as you asked in your question: person p; p = (person) 1234**
Yes, I already changed it, it worked. but from the error in the execution, I saw no use.
@user56294: That’s what I tried to explain earlier. You only do things like this when you’re programming a driver for a device, or programming for an embedded device. In such cases there are fixed memory addresses to communicate with the hardware.
It’s like I said in the reply, you have to know what to do with it...the comment from @C. E. Gesser above makes sense, sometimes there are hardware devices that appear as a memory address, so it makes sense. For example, in DOS the video is a memory area, so by tapping a pointer to that memory you can write to the video by changing the memory via a pointer.
opa, how cool in.
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It is possible yes, but it only makes sense if this address is mapping some device, whose data layout is the same as struct
– C. E. Gesser
A second struct?
– user56294
Look at the answer that has already been given below. You can do this, but it is assumed that at 1234 there are 20 bytes representing the name plus 4 representing age as a
int. If not, anything can happen.– C. E. Gesser