2
I have a div that brings a select from the bank, but it can only be shown if it meets a condition. It comes like this:
<div id="conteudo" style="display: none;">
If she meets this condition:
if (get('data_do_descredenciamento') != ''), then the display of div must change to style="display: show;".
How can I set this condition in PHP?
6
Option 1:
<div style="<?php echo get('data_do_descredenciamento') != '' ? 'show' : 'none'; ?>">
</div>
Option 2:
<div style="<?php if (get('data_do_descredenciamento') == '') { echo 'display: none;' }">
</div>
Option 3:
<?php if (get('data_do_descredenciamento') != '') { ?>
<div>
</div>
<?php } ?>
Just suggesting an improvement, the return show is unnecessary, could be exchanged for null why the option show inside the property display there is no.
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Instead of hiding the div it’s no longer simple nor put her on the way out?
– Bacco