How do I know if today’s date is Saturday or Sunday (weekend) in PHP?

Question

I want to know the simplest possible way to find out if today’s date is Saturday or Sunday in PHP.

What are the possible ways to do this?

Answer 1

To find out if the current date is weekend:

date( 'N' ) > 5       // hora local
gmdate( 'N' ) > 5     // GMT

• Parameter 'N' returns the days of 1 to 7, being 1 Monday, and 7 Sunday, and works from PHP 5.1 onwards.

• Omitting the second parameter causes the date to return the current date/time, which is the default.

• To make operations without taking into account the Timezone from the server, just use gmdate() in place of date(), in every instance.

Just out of curiosity, if you need the 'w' (minusculo!) that’s enough:

! ( date( 'w' ) % 6 )   

or even

( date( 'w' ) % 6 ) == 0

• 'w' returns the day of the week in the range of 0 to 6, being 0 Sunday and 6 Saturday.

• The operator %, of split rest, makes both the values 0 (Sunday) as 6 (Saturday) result in zero, which indicates weekend.

• The ( ) are required as it is PHP, and the order of Evaluation is weird.

If you want to simplify the case of 'w', just reverse the test:

echo date( 'w' ) % 6 ? 'Não é fim de semana' : 'é fim de semana';

See in the manual all the parameters of date():

http://php.net/manual/en/function.date.php

Answer 2

if (date('w') == 0 or date('w') == 6) {
    echo "É final de semana ";
}

Answer 3

If you have PHP >= 5.1:

function isWeekend($date) {
    return (date('N', strtotime($date)) >= 6);
}

but:

function isWeekend($date) {
    $weekDay = date('w', strtotime($date));
    return ($weekDay == 0 || $weekDay == 6);
}

Translated from https://stackoverflow.com/questions/4802335/checking-if-date-is-weekend-php

Answer 4

Another way to know this is by taking the day in full. As in English the Saturday (Saturday) and Sunday (Sunday) begin with the letter S, just know this.

Behold:

if (substr(date('D'), 0, 1) === 'S') {

   echo 'final de semana';

}

If you are using PHP 5.4, you can delete substr() and replace with [0], known as Function array Dereferencing.

Example:

if (date('D')[0] === 'S') {

   echo 'final de semana';

}

Answer 5

I’ll give my pinch on my own answer:

in_array(date('w'), [0, 6])

In the case, w returns the day of the week in numerical format, where 0 it is Sunday and 6, saturday.

in_array will do the job of checking if the value of the first parameter ($needle, translating is "needle") lies in the array that must be passed in the second parameter ($haystack, which means "haystack").

Answer 6

<?php
$domingo = mktime(0, 0, 0, 6, 19, 2016); // 19/6/2016
$sabado = mktime(0, 0, 0, 7, 2, 2016); // 2/7/2016
$sexta = mktime(0, 0, 0, 6, 24, 2016); // 24/6/2016

echo "Data 01 : " . (fimDeSemana($domingo) ? "fim de semana" : "dia de semana");
echo "<br/>";
echo "Data 02 : " . (fimDeSemana($sabado) ? "fim de semana" : "dia de semana");
echo "<br/>";
echo "Data 03 : " . (fimDeSemana($sexta) ? "fim de semana" : "dia de semana");


function fimDeSemana($date)
{
    return date("D", $date) === "Sat" or date("D", $date) === "Sun";
}

Exit:

Data 01 : fim de semana
Data 02 : fim de semana
Data 03 : dia de semana

Answer 7

Using the class Datetime

$str = null;
//$str = '2016-09-24';
$dt = new DateTime($str);
$weekend = ($dt->format('w') % 6) == 0;
var_dump($weekend);