String deserialization

Question

I caught the Retrofit Drivers field from the following json:

{
  "Drivers": [
    {
      "DriverID": 0,
      "Latitude": -23.642276336,
      "Longitude": -46.634615118
    },
    {
      "DriverID": 1,
      "Latitude": -23.64227916,
      "Longitude": -46.634592381
    }
  ],
  "Success": true
}

I have a list:

List drivers = MyModel.getDrivers();

So I made a drivers.get(0). toString() and got the following String:

{DriverID=0.0, Latitude=-23.642259377, Longitude=-46.634618813}

Now I want to make an deserialize on that list so I have something like:

driver.getDriverID()

I tried this way, but it didn’t work:

Master code:

Gson gson = new Gson();
Type listType = new TypeToken<List<Drivers>>(){}.getType();
String str = drivers.get(0).toString();
List<Drivers> teste = (List<Drivers>) gson.fromJson(str, listType);

Java drivers.:

public class Drivers {
    @SerializedName("DriverID")
    private Integer DriverID;

    public Integer getDriverID() {  
        return DriverID;
    }

    public void setDriverID(Integer driverID) {
        DriverID = driverID;
    }
}

Answer 1

Try it this way:

Gson gson = new Gson();
Type listType = new TypeToken<List<Drivers>>(){}.getType();
String str = drivers.get(0).toString();
Drivers teste =   gson.fromJson(str, Drivers.class);
teste.getDriverID();

How do you pick only one item from the list:

String str = drivers.get(0).toString();

He will only be her element:

{DriverID=0.0, Latitude=-23.642259377, Longitude=-46.634618813}

Then your result will be one Drivers

Answer 2

The problem is that you’re putting one objeto within a array.

In view of the fact that, drivers.get(0) returns a driver object, your code needs to look something like:

Gson gson = new Gson();
String str = drivers.get(0).toString();
Drivers driver = gson.fromJson(str, Drivers.class);