1
Good evening, you guys,
 I bring in a table a result of a select of a bank, but in the result:  
echo"". $T_TOTAL."";
I’m bringing a variable because I had to do a treatment to get my result.
Doubt: How can I add the result of the variable?
<?php
    echo"<table class='datatable table table-hover table-bordered table-responsiv'>";
    echo"<thead>";
    echo"<tr>";
    echo"<th>CELULAR</th>";
    echo"<th>DESCRIÇÃO</th>";
    echo"<th>TEMPO</th>";
    echo"<th>VALOR</th>";
    echo"</tr>";
    echo"</thead>";
    echo"<tbody>";       
    echo"<tr>";
    while ($row = mysql_fetch_array($query_pesquisa)) {
    $TEMPO=$row['VALOR'];
    $T_TOTAL=$TEMPO / 6 * 0.015 ;
    echo"<td>".$row['CELULAR']."</td>";
    echo"<td>".$row['DESCRICAO']."</td>";
    echo"<td>".$row['MINUTOS']."</td>";
    echo"<td>".$T_TOTAL."</td>";
    echo"</tr>";
      } 
   echo" </tbody>";
   echo" </table>";   
?>

Good afternoon, but I need that calculation (6 * 0.015), if I let it not go right ?
– Chefe Druida
It was just a suggestion because if this expression is fixed, then I suggested to leave the calculated value. Therefore, 6 multiplied by
0.015results0.09. But if you want you can leave it as6 * 0.015. Of course it’s a ridiculous performance gain, but anyway it’s a logic for optimization. The fewer processes to achieve the same result and, efficiently, the better.– Daniel Omine
Um got it, thanks for detailing and it’s exactly what I needed,.
– Chefe Druida