Error in IF condition

Question

I’m doing a program in PHP but I’m having a problem. I want when $user_info is the same as Tiago Goncalves, to show the user’s image. The truth is that all 3 images are shown on the website.

HTML

Answer 1

Note that you are not using the comparator but assigning the value to the variable:

if( $user_info['nome'] = 'Tiago Gonçalves')

The right thing would be:

if( $user_info['nome'] == 'Tiago Gonçalves')

Correcting the code:

if( $user_info['nome'] == 'Tiago Gonçalves'){
   echo "<img src='img/users/Tiago.jpg'>";
}
else if( $user_info['nome'] == 'Alexandre Salgado'){
   echo "<img src='img/users/Alexandre.jpg'>";
}
else if( $user_info['nome'] == 'Ricardo Cardoso'){
   echo "<img src='img/users/Ricardo.jpg'>";
}