Read XML received from ajax - PHP

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In php using the command var_dump($_FILES ['filexml']); I receive the following values from ajax

array(5) {
  ["name"]=>
  string(56) "nomeficticio.xml"
  ["type"]=>
  string(8) "text/xml"
  ["tmp_name"]=>
  string(14) "/tmp/phpoqnomeficticio"
  ["error"]=>
  int(0)
  ["size"]=>
  int(16536)
}

Through this data, how can I read this XML file? with PHP I even tried to use the command simplexml_load_file($_FILES['filexml']); but made the following mistake:

simplexml_load_file() expects Parameter 1 to be a Valid path, array Given

php ajax xml

  • You are passing the entire array as parameter, while you need the path of a file to read. I think, in your case, simplexml_load_file($_FILES['filexml']['name']) is the most appropriate, as long as the path in this array field is the correct one

  • @Caiofelipepera Hmmm, I need to upload first so I can read the XML? or I can read the xml without necessarily uploading it (save to some directory)

  • The guys already got the jump right there, hahaha. But the thing was kind of

2 answers

3


The array already tells you where the file is located. Just open it:

simplexml_load_file($_FILES['filexml']['tmp_name']);

However, it is not recommended to treat a file that is in a temporary directory, as the OS itself can clean this directory from time to time. You’d rather move him before that:

$basename = basename($_FILES['filexml']['tmp_name']);
move_uploaded_file($_FILES['filexml']['tmp_name'], __DIR__ . $basename);
simplexml_load_file( __DIR__ . $basename);

  • Simmm, that’s right Worked perfectly, thanks for the tip.

  • The two answers were great, but this one answered me also another small question that had here

3

You only need to use tmp_name instead of name. Take an example:

<?php
if(isset($_FILES['input_file'])){
    $xml = simplexml_load_file($_FILES['input_file']["tmp_name"]);
    echo '<pre>';
    var_dump($xml);
    echo '</pre>';
}
?>
<form class="frm" method="post" enctype="multipart/form-data" novalidate="novalidate">
    <input type="file" name="input_file"/>
    <input type="submit" value="Enviar"/>
</form>

I hope I’ve helped!

If it works out, I’d be happy to give me an upvote and choose my answer.

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