How to take a value inside an array with PP

Question

I have an API with some information and I want to get the Genre: Samba/Pagode

stdClass Object
(
    [id] => 46484422
    [title] => Raça Negra e Amigos II (Ao Vivo)
    [upc] => 7891430177379
    [link] => https://www.deezer.com/album/46484422
    [share] => https://www.deezer.com/album/46484422?utm_source=deezer&utm_content=album-46484422&utm_term=0_1529271972&utm_medium=web
    [cover] => https://api.deezer.com/album/46484422/image
    [cover_small] => https://e-cdns-images.dzcdn.net/images/cover/45f27e183464715a67145b985dcbbd82/56x56-000000-80-0-0.jpg
    [cover_medium] => https://e-cdns-images.dzcdn.net/images/cover/45f27e183464715a67145b985dcbbd82/250x250-000000-80-0-0.jpg
    [cover_big] => https://e-cdns-images.dzcdn.net/images/cover/45f27e183464715a67145b985dcbbd82/500x500-000000-80-0-0.jpg
    [cover_xl] => https://e-cdns-images.dzcdn.net/images/cover/45f27e183464715a67145b985dcbbd82/1000x1000-000000-80-0-0.jpg
    [genre_id] => 79
    [genres] => stdClass Object
        (
            [data] => Array
                (
                    [0] => stdClass Object
                        (
                            [id] => 79
                            [name] => Samba/Pagode
                            [picture] => https://api.deezer.com/genre/79/image
                            [type] => genre
                        )

                )

        )

    [label] => Som Livre

My Code:

<?php
  $api = "https://api.deezer.com/album/46484422";
  $url = file_get_contents("$api");
  $json = json_decode($url, true); //This will convert it to an array
  $titulo = $json['title'];
  $capa1000x1000 = $json['cover_xl'];
  $musicas = $json['tracks'];
  $genero = $json['genres'];
?>

<?php echo $genero ?>

However, I wanted to write the name of the genre, but this error:

Notice: Array to string Conversion in api.php on line 29 Array

Answer 1

Since it’s an array, and there may be more than one genre, you don’t want to have a cycle to catch all genres?

If you just want the first one, it would just be $json['genres']['data'][0]['name'], but if one of these keys, genres, data is not defined, will give error, even if data empty because you’re always trying to access the first.

EDIT

Example of the HTML cycle. In the place on the page where you want to display the generos, you can put something like this. It doesn’t need to be a <ol>, can be any other html element that you then need to use CSS to style.

// ... html anterior que está na pagina ...

<ol>
<?php foreach ($json['genres']['data'] as $genero): ?>
    <li><?php echo $genero ?></li>
<?php endforeach; ?>
</ol>

// ... resto do html