Posts by perrylopes • 3 points

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  Q: The inclusion of data is not occurring in the database, and the connection and variable is arriving in the function

  Function gravar_task($connection, $task) { if(mysqli_connect_error($connection)){ echo 'Sem conexão com banco de dados'; die(); } $sqlGravar = " INSERT INTO tarefas (nome, descricao, prioridade)…

  php mysqli

  asked 8 years, 7 months ago perrylopes 3