Posts by Alan Sousa • 1 point
1 post
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votes5
answers57768
viewsA: Count equal records with SELECT DISTINCT and COUNT
I think this one might help you!! SELECT Nome, COUNT(Nome) AS Qtd FROM Clientes GROUP BY Nome ORDER BY COUNT(Nome) DESC
1 post
-2
votes5
answers57768
viewsI think this one might help you!! SELECT Nome, COUNT(Nome) AS Qtd FROM Clientes GROUP BY Nome ORDER BY COUNT(Nome) DESC