php Session - destroy all Sessions and keep only one active

Question

Hello,

I need to destroy all Sesssions when logging out a system except for just one... someone would know how to implement this with php?

For example:

• Let’s say I have 5 active sesssions when the user is logged in:

  $session1 = $_SESSION['session1'];
  $session2 = $_SESSION['session2'];
  $session3 = $_SESSION['session3'];
  $session4 = $_SESSION['session4'];
  $session5 = $_SESSION['session5'];
  

• When logging out, I want to destroy 4 of these Sesssions, but there is one that I need to keep active... how would I look in this part? I tried so:

  session_start();
  
  if(!isset($_SESSION['session4'])){
  
        session_destroy(); 
  
  }//end if
  

  • so it didn’t work out... as it would be right?

Answer 1

You could create a variable temporarily to receive the session variable value, destroy all and then create only the session variable you want.

$auxiliar = $_SESSION['session4'];

session_unset();

$_SESSION['session4'] = $auxiliar;

Another, more direct way to do this:

$_SESSION = ['session4' => $_SESSION['session4']]

Answer 2

You are misreading $_SESSION represents the current session, is an associative array with session data, $_SESSION['session1'] represents variable saved in that session.

to delete a session variable you can do

unset($_SESSION['session1']);

to eliminate all variables

$_SESSION = array();

to delete all variables except variable with session1 key'

foreach ($_SESSION as $key => $value) {

    if ($key != 'session1') {

        unset($_SESSION[$key]);

    }
}

Answer 3

You giving session_destroy(); you will destroy all the Session, for you to destroy only the specifics use unset();

therefore:

unset($_SESSION['session1'], $_SESSION['session2']);

RESULT: you will destroy the 2 Session (or the ones you put inside the unset(); ).