Recover JSON in PHP

Question

I saw many forums but still not solved for me

HTML

<div class="form-group col-xs-12 col-sm-5 col-md-6 col-lg-6">
  <label for="banco">Banco</label>
  <select id="banco" type="number" class="form-control" required="" >
    <option value="">Selecione</option>
    <option value='{"sigla" : "bradesco", "banco": "Bradesco"}'>Bradesco</option>
    <option value='{"sigla" : "bb", "bank": "Brasil"}'>Brasil</option>
    <option value='{"sigla" : "cef", "bank": "Caixa Economica Federal"}'>Caixa Econ&ocirc;mica Federal</option>
    <option value='{"sigla" : "itau", "bank": "Itau"}'>Ita&uacute;</option>
    <option value='{"sigla" : "santander_banespa", "bank": "Santander"}'>Santander</option>
  </select>
</div>

Javascript

I have in Javascript that makes the following sending:

function salvar(){
jQuery('#form').submit(function () {
    var banco       = document.getElementById('banco').value;
     $.ajax({
     type    : 'post',
     dataType: 'json',
     url     : 'function/conta.php',
     beforeSend : carregando,
     data: {                
           'banco'      : JSON.stringify(banco),         
           },
           success: function (data) {
           //alert(data.retorno);
           if (data.retorno == 1) {
           sucesso('Operação realizada com sucesso!');
           }
           else {
           errosend('Não foi possível realizar operação. Verifique se todos os campos estão preenchidos ');
          }
        }
      });
    return false; 
 });
}

PHP

In PHP it returns:

if(isset($_POST['banco'])){
    $banco = $_POST['banco'];
}

$bank1 = json_decode($banco);

foreach ($bank1 as $item => $value) {
        echo $value->{'bank'};
    }

But the message it gives is:

Warning: Invalid argument supplied for foreach() in

Each case is a case, because in another file I use this block foreach works for

Answer 1

There are several ways to do what you need, but I’ll use your concept.

In the Javascript try to send the contents of option selected as he is:

function salvar(){
jQuery('#form').submit(function () {
    var banco       = document.getElementById('banco').value;
     $.ajax({
                type    : 'post',
                dataType: 'json',
                url     : 'function/conta.php',
                beforeSend : carregando,
                data: {

                    'banco'      : banco,

                },
                success: function (data) {
                    //alert(data.retorno);
                    if (data.retorno == 1) {
                        sucesso('Operação realizada com sucesso!');
                    }
                     else {
                        errosend('Não foi possível realizar operação. Verifique se todos os campos estão preenchidos ');
                    }
                }
              });
        return false; 
});
}

In PHP decode with json_encode

if(isset($_POST['banco'])){
    $banco = $_POST['banco'];
}

$bank1 = json_decode($banco);

echo $bank1->sigla.'<br />';
echo $bank1->bank;

The mistake I understand is that option is sending a unique object and not an array of objects, so it does not need to be caught (and will not even give) by foreach that just loops with arrays. With this, you can take the object directly.

NOTE: I noticed that in your options has a json value called bank instead of bank.. Be careful with this, because it may give future errors in the checks.